Math, asked by rajneeshshukla3098, 6 months ago

2(2b-3c)-2[4c-2{c-3(b-c)}-3b]

Answers

Answered by soodanvi11

0

Step-by-step explanation:

4b-6c-2[4c-2{c-3b+3c}-3b]

=4b-6c-2[4c-2c+6b-6c-3b]

=4b-6c-8c+4c-12b+12c+6b

=4b-12b+6b-6c-8c+4c+12c

=10b-12b-14c+16c

=-2b+2c

=2c-2b

=2(c-b)

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