Question

(2^2m×2^5m+1)=2^15 please ​

Answer 1

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Answer 2

Simplifying

(m + 3)(-2m2 + 5m + -1) = 0

Reorder the terms:

(3 + m)(-2m2 + 5m + -1) = 0

Reorder the terms:

(3 + m)(-1 + 5m + -2m2) = 0

Multiply (3 + m) * (-1 + 5m + -2m2)

(3(-1 + 5m + -2m2) + m(-1 + 5m + -2m2)) = 0

((-1 * 3 + 5m * 3 + -2m2 * 3) + m(-1 + 5m + -2m2)) = 0

((-3 + 15m + -6m2) + m(-1 + 5m + -2m2)) = 0

(-3 + 15m + -6m2 + (-1 * m + 5m * m + -2m2 * m)) = 0

(-3 + 15m + -6m2 + (-1m + 5m2 + -2m3)) = 0

Reorder the terms:

(-3 + 15m + -1m + -6m2 + 5m2 + -2m3) = 0

Combine like terms: 15m + -1m = 14m

(-3 + 14m + -6m2 + 5m2 + -2m3) = 0

Combine like terms: -6m2 + 5m2 = -1m2

(-3 + 14m + -1m2 + -2m3) = 0

Solving

-3 + 14m + -1m2 + -2m3 = 0

Solving for variable 'm'.

The solution to this equation could not