2^2m + 3 × 2^-5 = 2^m+3
Find m
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Solution
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3m+2(m+2)=20−(2m−5)
⇒ 3m+2m+4=20−2m+5
⇒ 5m+4=25−2m
⇒ 5m+2m=25−4
⇒ 7m=21
∴ m=
7
21
∴ m=3
i got this one
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