Question

2^2x -1 = 1/8^x−3 find x​

Answer 1

Answer:

here,

or,2^(2x-1) = 1/(8^x-3)

or, 2^(2x-1) = 1/8^x * 8^-3

or, 2^(2x-1)= 8^3/8^x

or, 2^(2x-1) = 8^(3-x)

or, 2^(2x-1) = 2^{3(3-x)}

or, 2^(2x-1) = 2^(9-3x)

now, comparing power, we get

or, 2x-1 = 9-3x

or, 5x = 10

hence, x =2

i hope this is helpful for you

   

Step-by-step explanation: