Question

(2^2x+1)=17×(2^x)-2^3
value of x?​

Answer 1

Answer:

hola mate

see the attachment

hope It helps u

Answer 2

Step-by-step explanation:

${2}^{2x} \times 2 = 17 \times {2}^{x} - {2}^{3} \\ = ( {2}^{x} ) {}^{2} \times 2 = 17 \times {2}^{x} - {2}^{3} \\ let \: {2}^{x} = y \\ = {y}^{2} \times 2 = 17 \times y - 8 \\ 2 {y}^{2} - 17y + 8 = 0 \\ 2 {y}^{2} - 16y - y + 8 = 0 \\ 2y(y - 8) - 1(y - 8) = 0 \\ (2y - 1)(y - 8) \\ 2y - 1 = 0 \\ y = \frac{1}{2} \\ \\ y - 8 = 0 \\ y = 8 \\ \\ so \\ \\ {2}^{x } = 8 \\ {2}^{x} = {2}^{3} \\ x = 3 \\ \\ {2}^{x} = \frac{1}{2} \\ {2}^{x} = {2}^{ - 1} \\ = x = - 1$

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