Math, asked by tapasvi28, 1 year ago

2^2x+1=17*2^x-8. please solve it

Answers

Answered by sonukumar985
1
2^2x+1=17×2^x-8


(2)^2x+1-(x-8) =17 [a^m÷a^n=(a)^m-n]
(2)^2x+1-x+8 =17
x+9=0
x=-9
(2)^-9 =17
17×(2)^9 [a^-m=1/a^m]
17×512=8704 ans
please reply fast
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