Question

2^2x + 1 = 32( find x pls fast )

Answer 1

Answer:

2^(2x+1)=32

=> 2^(2x+1)=2×2×2×2×2

=> 2^(2x+1)=2^5

=> 2x+1=5

=> 2x=5-1

=> 2x=4

=> x=4/2

=> x=2

Answer 2

${2}^{2x + 1} = 32 \\ \\ {2}^{2x + 1} = {2}^{5} \\ \\ 2x + 1 = 5 \\ \\ 2x = 4 \\ \\ x = 2$