Question

2^(2x-1)- 4^(x-1) = 784

Answer 1

Answer:

nahi pata

Step-by-step explanation:

u bhi nahi pata

Answer 2

Answer:

x = 5.807

Step-by-step explanation:

In the given equation,

$2^{2x-1}-4^{x-1}=784$

So, on simplifying the equation further we get,

$\frac{2^{2x}}{2}-\frac{4^{x}}{4}=784\\4^{x}(\frac{1}{2}-\frac{1}{4})=784\\4^{x}(\frac{1}{4})=784\\4^{x}=784\times 4=3136\\4^{x}=3136$

Now, in this equation taking log on the both sides we get,

Because, we know that from the property of logarithms that,

$logA^{x}=xlogA$

So using the same in the equation we get,

$log4^{x}=log3136\\xlog4=log3136\\x=\frac{log(3136)}{log(4)}\\x=\frac{3.4963}{0.602}\\x=5.807$

Therefore, on doing that we find out that the value of 'x' is 5.807.

Hence, x = 5.807