Question

2(2x-1/x+3) - 3(x+3/2x-1)= 5​

Answer 1

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Answer 2

Answer:

{- 10, - 0.2}

Step-by-step explanation:

$2(\frac{2x-1}{x+3})$$-3(\frac{x+3}{2x-1})$ = 5

$\frac{2(2x-1)^2-3(x+3)^2}{(x+3)(2x-1)}$ = 5

2(4x² - 4x + 1) - 3(x² + 6x + 9) = 5(2x² + 5x - 3)

8x² - 8x + 2 - 3x² - 18x - 27 = 10x² + 25x - 15

5x² - 26x - 25 - 10x² - 25x + 15 = 0

- 5x² - 51x - 10 = 0

5x² + 51x + 10 = 0

D = 51² - 200 = 49²

$x_{12}$ = ( - 51 ± 49) / 10

$x_{1}$ = - 10

$x_{2}$ = - 0.2