Question

2(2x-1/x+3)-3(x+3/2x-1)=5​

Answer 1

Answer:

hope it helps u..!!!!

Step-by-step explanation:

Mark me as brainiest!!!

Answer 2

Answer:

$2( \frac{2x - 1}{x + 3} )\: - \: 3 (\frac{x + 3}{2x - 1} ) = 5$

$\\ 2 \frac{{(2x - 1)}^{2} - 3 {(x + 3)}^{2} }{(x + 3)(2x - 1)} = 5$

$\frac{2( {4x}^{2} - 4x + 1) - 3( {x}^{2} + 6x + 9) }{2 {x}^{2} -x + 6x + 3 } = 5$

$= > 8 {x}^{2} - 5x + 2 - 3 {x}^{2} - 18x - 27 = 10 {x}^{2} + 25x - 15$

$= > 5 {x}^{2} - 26x - 25 = 10 {x}^{2} + 25x - 15$

$= > 5 {x}^{2} + 51x + 10 = 0$

$\\ = > 5 {x}^{2} + x + 50x + 10 = 0$

$= > x(5x + 1) + 10(5x + 1) = 0$

$= > (5x + 1)(x + 10) = 0$

$= > \: x = - 10 \\ \times = - \frac{ 1}{5}$

_________________

Therefore x = -10

x = -1/5

__________