2(2x-1/x-3)-3(x-3/2x-1)=5
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x ≠ -3 , 1/2
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Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
How to solve your problem
2
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2
−
1
⋅
1
−
3
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−
3
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−
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⋅
3
2
⋅
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=
5
2(2x-1 \cdot \frac{1}{x}-3)-3(x-1 \cdot \frac{3}{2} \cdot x-1)=5
2(2x−1⋅x1−3)−3(x−1⋅23⋅x−1)=5
Solve
1
Find common denominator
2
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2
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1
−
3
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3
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3
2
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5
2(2x+\frac{-1}{x}-3)-3(x-1 \cdot \frac{3}{2} \cdot x-1)=5
2(2x+x−1−3)−3(x−1⋅23⋅x−1)=5
2
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⋅
2
+
−
1
+
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3
)
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3
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⋅
3
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=
5
2(\frac{x \cdot 2x}{x}+\frac{-1}{x}+\frac{x\left(-3\right)}{x})-3(x-1 \cdot \frac{3}{2} \cdot x-1)=5
2(xx⋅2x+x−1+xx(−3))−3(x−1⋅23⋅x−1)=5
2
Combine fractions with common denominator
3
Re-order terms so that constants are on the left
4
Combine exponents
5
Re-order terms so that constants are on the left
6
Rearrange terms
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Multiply the numbers
8
Combine multiplied terms into a single fraction
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Find common denominator
10
Combine fractions with common denominator
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Multiply the numbers
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Combine like terms