Question

[2^2x-2+10]÷13=2 find the value of x​

Answer 1

$\textbf{Given:}$

$\dfrac{2^{2x-2}+10}{13}=2$

$\textbf{To find:}$

$\text{The value of x}$

$\textbf{Solution:}$

$\text{Consider,}$

$\dfrac{2^{2x-2}+10}{13}=2$

$\implies\,2^{2x-2}+10=26$

$\implies\,2^{2x-2}=26-10$

$\implies\,2^{2x-2}=16$

$\implies\,2^{2x-2}=2^4$

$\text{Equating powers on bothsides, we get}$

$2x-2=4$

$2x=4+2$

$2x=6$

$\implies\boxed{\bf\,x=3}$

$\therefore\textbf{The value of x is 3}$

$\textbf{Find more:}$

If 5^x-1 + 5^x+1=650 then find x​

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If a is equal to 2 power x minus 1 upon 2 power x - 2 and b is equal to 2 power minus x upon 2 power x + 1 and a minus b is equal to zero then find the value of x

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Answer 2

Answer:

1

Step-by-step explanation:

[2²ˣ⁻²+10]÷13=2

[2²ˣ⁻²+10]=2*13  

(2)²ˣ⁻²=26-10

(2)²ˣ⁻²=16

(2)²ˣ⁻²=2⁴     [∵16 can be written as 2⁴]

2x-2=4         [∵mᵃ=mᵇ  =  a=b]

2x=4-2

x=2÷2

∴x=1