Question

2^2x+2=4^2x-1 find the value of x​

Answer 1

Answer:

x=2

Step-by-step explanation:

2^(2x+2)=4^(2x-1)

4=2^2

Instead of 4 we can write 2^2 so that the base numbers will be 2

2^(2x+2)=(2^2)^(2x-1)

So we get 2 raise to 2x +2=2 raise 2 all raise to 2x-1

We have studied a raise to m all raise to n is a raise to m*n

(a^m)^n=a^(mn)

Here the m is 2 and n is 2x-1

mn=2 (2x-1)

mn=4x-2

Thus we will get

2^(2x+2)=2^(4x-2)

The base numbers are equal so the power will also be equal....

2x+2=4x-2

Solve......

2+2=4x-2x

4=2x

2x=4

x=4/2

x=2

Hope it helps ...

plse mark me as brainliest......

Answer 2

Answer:

x=2 this is the correct answer