Question

2^2x+2=4^2x-1
Solve this​

Answer 1

$2^{(2x+2)}$ = $4^{(2x-1)}$

= $2^{(2x+2)}$ = $2^{2(2x-1)}$

= $2^{(2x+2)}$ = $2^{(4x-2)}$

 

Bases are same so exponent are also equal

2x+2 = 4x - 2

2x = 4

x = 2

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Answer 2

$2^{(2x+2)}$ = $4^{(2x-1)}$

= $2^{(2x+2)}$ = $2^{2(2x-1)}$

= $2^{(2x+2)}$ = $2^{(4x-2)}$

 

Bases are same so exponent are also equal

2x+2 = 4x - 2

2x = 4

x = 2