2^2x - 2^x+3 + 2^4 = 0 how to prove this?
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22x+3(2x)−4=022x+3(2x)−4=0
(2x)2+3(2x)−4=0(2x)2+3(2x)−4=0
Let u=2xu=2x
u2+3u−4=0u2+3u−4=0
(u−1)(u+4)=0(u−1)(u+4)=0
u=1u=1or u=−4u=−4
2x=12x=1 or 2x=−42x=−4
Since 2x2x can never be negative, we only need to solve 2x=12x=1 which can easily be solved to find x=0x=0 as the only real solution to the original equation
(2x)2+3(2x)−4=0(2x)2+3(2x)−4=0
Let u=2xu=2x
u2+3u−4=0u2+3u−4=0
(u−1)(u+4)=0(u−1)(u+4)=0
u=1u=1or u=−4u=−4
2x=12x=1 or 2x=−42x=−4
Since 2x2x can never be negative, we only need to solve 2x=12x=1 which can easily be solved to find x=0x=0 as the only real solution to the original equation
Anvi9876:
how did we get 22
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