Question

2^2x-2^x+3+2^4=0 solve for x​

Answer 1

Step-by-step explanation:

2^2x-2^x+3+2^4=0

(2^x)^2 - ( 2x.2^3)+2^4=0

(2^x)^2 - 8(2^x)+ 16 = 0

LET 2^x=y

y^2-8y+16=0

y^2-4y-4y+16=0

y(y-4)-4(y-4) =0

(y-4) (y- 4) =0

y - 4 =0 y - 4 = 0

y = 4. y = 4

Put. 2^x= 4

2^x= 2^2

X = 2