Question

[(2^2x*4*2^x-8^x)/{(2^5)^3*9}] = (1/24)​

Answer 1

Solution :-

→ [(2^2x*4*2^x-8^x)/{(2^5)^3*9}] = (1/24)

→ [2^(2x) * (2)² * 2^(x) - (2³)^x] / [2⁵)³ * 9] = (1/24)

using :-

• a^m * a^n * a^p = a^(m + n + p)
• (a^m)^n = a^(m * n)

→ [2^(2x + 2 + x) - 2^(3x)] / (2¹⁵ * 9) = (1/24)

→ [2^(3x + 2) - 2^(3x)]/(2¹⁵ * 9) = (1/24)

→ 2^(3x + 2 - 3x) / (2¹⁵ * 9) = (1/24)

→ 2²/(2¹⁵ * 9) = (1/24)

→ 1/(2¹³ * 9) = 1/24

→ 1/(2¹³ * 3) = 1/8

→ 1/(2¹³ * 3) = 1/2³

→ 1/(2¹⁰ * 3) = 1

→ LHS ≠ RHS .

we can not solve further . Please check the question once and write it properly .

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let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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