2(2x-5y)(3x+4y)-6(2x-5y)(x-y). factorise by taking out the common factors
please answer this with full process
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Answered by
7
Solution :
Given 2(2x-5y)(3x+4y)-6(2x-5y)(x-y)
= 2(2x-5y)[3x+4y - 3(x-y)]
= 2(2x-5y)[ 3x+4y-3x+3y ]
= 2(2x-5y)( 4y+3y )
= 2(2x-5y)(7y)
= 14(2x-5y)y
••••
Given 2(2x-5y)(3x+4y)-6(2x-5y)(x-y)
= 2(2x-5y)[3x+4y - 3(x-y)]
= 2(2x-5y)[ 3x+4y-3x+3y ]
= 2(2x-5y)( 4y+3y )
= 2(2x-5y)(7y)
= 14(2x-5y)y
••••
Answered by
6
This is your answer mate.
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