Question

2^(2x+8) - 32 (2^x) + 1 = 0

Answer 1

Step-by-step explanation:

2^(2x+8) - 32 (2^x) =0

2^(2x+8)=32 (2^x)

2^(2x+8)=2^5(2^x)

bases are equal so powers must be equate

2x+8=5x

5x-2x=8

3x=8

then

X=8/3

Answer 2

Step-by-step explanation:

2^(2x+8)-32(2^x)= -1

2^(2x+8)-2^(5+x)=-1

multiply by 2 on both sides

2(2^(2x+8)-2^(5+x))= -2^1

2^(2x+9)-2^(6+x)= -2^1

since the base are eq the powers are also eq

2x+9-6-x=-1

x+3=-1

x=(-4)

i hope my ans helped u