2√2x²-9x+5√2 find the zeros of the following quadratic polynomial and verify the coefficient
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2√2x^2-4x-5x+5√2
2√2x(x-√2) - 5(x-√2)
(x-√2)(2√2x-5)
now,
p(x)=0 ->(x-√2)(2√2x-5)=0
x-√2=0 or 2√2x-5=0
x=√2 or x=5/2√2
verification,
let α=√2 and β=5/2√2
α+β=(√2)+(5/2√2) = 4+5/2√2 =9/2√2 =-(coefficient of x) /(coefficient of x ^2)
αβ=(√2)(5/2√2) = 5√2/2√2
=(constant term)/(coefficient of x^2)
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here is the answer
i hope this helps you
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