Math, asked by cliffordsanchez24, 2 months ago

×-2; 2x³ - 11x² - 8x ± 11

Answers

Answered by Tituspal

0

Answer:

(×-2) (2x³ - 11x² - 8x ± 11)

= (2x^4- 11x^3- 8x^2+11x) -(4x^3- 22x^2 -16x+ 22)

= 2x^4- 11x^3- 8x^2+11x -4x^3+ 22x^2 +16x- 22

= 2x^4- 15x^3+ 14x^2+ 17x-22

Step-by-step explanation:

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