Question

2√2x4 +6√2x3 +x2 by 2√x2​

Answer 1

Answer:

(x-√3/2)(x+√3/2)=x²-3/2

g(x)=x²-3/2

p(x)=2x^4-2x³-7x²+3x+6

then q(x)=2x²-2x-4

⇒2x²-2x-4=2x²+2x-4x-4=2x(x+1)-4(x+1)=(2x-4)(x+1)

⇒2x-4=0 or ⇒ x+1=0

⇒x=2 or ⇒ x= -1

Answer 2

Answer:

Step-by-step explanation:Answer:

(x-√3/2)(x+√3/2)=x²-3/2

(x)=x²-3/2

(x)=2x^4-2x³-7x²+3x+6

(x)=2x²-2x-4

⇒2x²-2x-4=2x²+2x-4x-4=2x(x+1)-4(x+1)=(2x-4)(x+1)

⇒2x-4=0 or ⇒ x+1=0

⇒x=2 or ⇒ x= -1