Question

2/3= 1/3 + n . solve each of the following equations by using inverse operations
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Answer 1

SOLUTION

TO SOLVE

Using inverse operations

$\displaystyle \sf{ \frac{2}{3} = \frac{1}{3} + n }$

CONCEPT TO BE IMPLEMENTED

1. The additive identity = 0

2. For any real number x the additive inverse of x is - x so that - x + x = 0

EVALUATION

Here the given expression is

$\displaystyle \sf{ \frac{2}{3} = \frac{1}{3} + n } \: \: \: - - (1)$

$\displaystyle \sf{Now \: the \: additive \: inverse \: of \: \: \frac{1}{3} \: \: is \: - \frac{1}{3} }$

$\displaystyle \sf{Now \: adding \: both \: sides \: of \: (1) \: with \: - \frac{1}{3} \: \: we \: get}$

$\displaystyle \sf{ - \frac{1}{3} + \frac{2}{3} = - \frac{1}{3} + \frac{1}{3} + n } \: \:$

$\displaystyle \sf{ \implies \: \frac{ -1 + 2}{3} = 0 + n } \: \:$

$\displaystyle \sf{ \implies \: \frac{1}{3} = n } \: \:$

$\displaystyle \sf{ \implies \: n = \frac{1}{3} } \: \:$

FINAL ANSWER

Hence the required answer

$\boxed{ \displaystyle \sf{ \: \: n = \: \frac{1}{3} } \: \: }$

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