Question

2/√3-1 rationalize the denominator

Answer 1

Answer:

Hope this will help you

Answer 2

Answer:

$\sqrt{3} + 1$

Step-by-step explanation:

Whenever you want to rationalize the denominator, you have to multiply the numerator and denominator by such a number that the denominator becomes of the form a²-b².

Therefore,

$\frac{2}{ \sqrt{3} - 1 } \times \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1 } = \frac{2( \sqrt{3} + 1)}{ {( \sqrt{3} )}^{2} - {1}^{2} } = \frac{2( \sqrt{3} + 1 )}{3 - 1} = \frac{2( \sqrt{3} + 1)}{2} = \sqrt{3} + 1$