(-2+√-3^-1 simply and express each of the following
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( - 2 + √( - 3 ) )^-1
= 1 / - 2 + √3(-1)
since , we know , √ -1 = i
= 1 / -2 +√ 3i = 1 /√ 3i - 2
by rationalising denominator we get ,
1 / √3i - 2 × (√ 3i + 2 ) /( √3i + 2 )
= √3i + 2 / 3i^2 - 4
= 2 + √3i / -3 - 4
=( 2 + √3i )/ - 7
= (-2 / 7) + (-√3 / 7 ) i
= a + bi
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= 1 / - 2 + √3(-1)
since , we know , √ -1 = i
= 1 / -2 +√ 3i = 1 /√ 3i - 2
by rationalising denominator we get ,
1 / √3i - 2 × (√ 3i + 2 ) /( √3i + 2 )
= √3i + 2 / 3i^2 - 4
= 2 + √3i / -3 - 4
=( 2 + √3i )/ - 7
= (-2 / 7) + (-√3 / 7 ) i
= a + bi
______________________________
|| : hope it helps : ||
______________________________
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