2/3^10×
(3/2)^2^5 =2/3 ^2n-2
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Answer:
(2/3) ^10* {(3/2) ^2} ^5=(2/3) ^2n-2
(2/3)^10*(3/2)^10= (2/3)^2n-2
(2/3)^10*(2/3)^(-10)= (2/3)^2n-2
(2/3)^(10–10)= (2/3)^2n-2
Comparing power now
2n-2= 0
2n=2
n= 2/2= 1 (ans.)
Formulas I used : a^n*a^m = a^(m+n).
(a^n)^m = a^n*m .
(a/b)^n
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