2+
3.18 Calculate at 25°C the electrode potential, of Mg Mg
electrode in which the concentration of Mg2+ ions is
0.1 M. Given E 27
- 2.36 V, R = 8.314 JK-1,
Mg-*/Mg
O
=
3.2
F = 96500 coulombs mol-1.
[Ans. - 2.3896 V
Answers
Answered by
1
Answer:
Mg
+
+e
−
→Mg,E
0
cell=−2.36V
E
cell
=E
cell
0
−
nF
RT
ln
[Mg
+
]
1
E
cell
=−2.30V−
1×96500
8.14×298K
=ln
0.1
1
E
cell
=−2.41V
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