^2 + 3 − 2^
2 + 17 − 7 − 11 = 0 When the axes are translated to the point
(2, 3), then find the original equation of curve.
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ANSWER
As origin is shifted to point (−2,3),
So, put, x=x+2 and y=y−3
⟹(x+2)2+2(y−3)−3=0
⟹x2+4x+4+2y−6−3=0
⟹x2+4x+2y−5=0
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