Question

√2+√3÷∛2-2√3=a+b√6
find the values of a and b in the following

Answer 1

Answer:

√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following√2+√3÷∛2-2√3=a+b√6

find the values of a and b in the following

Step-by-step explanation:

Answer 2

Answer:

$\frac{(\sqrt{2} + \sqrt{3} )}{ \sqrt[3]{2} - 2 \sqrt{3} } = a + b \sqrt{6} \\ \frac{1 + \sqrt{ \frac{3}{2} } }{ \sqrt{2} - \sqrt{6} } \\ taking \: conjugate \: of \: denominator \\ \frac{1 + \sqrt{ \frac{3}{2} } }{ \sqrt{2} - \sqrt{6} } \times \frac{{ \sqrt{2} + \sqrt{6} } }{{ \sqrt{2} + \sqrt{6} } } \\ \frac{ \sqrt{ {2} } + \sqrt{3} + \sqrt{6} + 3 }{2 - 6} \\ - \frac{3 + ( \sqrt{2} + \sqrt{3} + \sqrt{6} )}{4} \\ \\ here \: a = - \frac{3}{4} \\ \\ and \: b = - \frac{1}{ \sqrt{6} } ( \frac{ \sqrt{2} + \sqrt{3 } + \sqrt{6} }{4} )$