Question

{(-2/3)^-2}^3×(1/3)^-4×3^-1×1/6​

Answer 1

$= (( \frac{ - 2}{3} )^{ - 2} )^{3} \times ( \frac{1}{3} )^{ -4} \times {3}^{ - 1} \times \frac{1}{6} \\ = (( \frac{ - 3}{2} )^{2} )^{3} \times {3}^{4} \times \frac{1}{3} \times \frac{1}{6} \\ = ( \frac{9}{4} ) ^{3} \times {3}^{4} \times \frac{1}{18} \\ = \frac{ {3}^{6} }{ {2}^{6} } {}^ \times {3}^{4} \times \frac{1}{ {3}^{2} } \times \frac{1}{2} \\ = {3}^{6 + 4 - 2} \times {2}^{ - 6 - 1} \\ = {3}^{8} \times {2}^{ - 7} \\ = \frac{ {3}^{8} }{ {2}^{7} } \\ = \frac{6561}{128}$

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