Question

{(-2/3)^-2}^3×(1/3)^-4×3^-1×1/6

GIVE ANSWERS PLZ​

Answer 1

Step-by-step explanation:

$(( \frac{ - 2}{3} ) {}^{ - 2} ) {}^{3} \times ( \frac{1}{3} ) {}^{ - 4} \times 3 {}^{ - 1} \times \frac{1}{6}$

$= (( \frac{ - 2}{3} ) {}^{ - 2} ) {}^{3} \times (\frac{1}{3}) \times ( \frac{1}{3} ) {}^{ - 4} \times \frac{1 }{3} \times \frac{1}{6}$

$= ( \frac{ - 2}{3} ) {}^{ - 6} \times ( \frac{1}{3} ) {}^{ - 4 + 1} \times \frac{1}{6}$

$( \frac{3}{ - 2} ) {}^{6} \times ( \frac{1}{3} ) {}^{ - 3} \times \frac{1}{6}$

$= \frac{3 {}^{6} }{( - 2) {}^{6} } \times (\frac{3 }{1} ) {}^{3} \times \frac{1}{6}$

$= \frac{3 {}^{6 +3 } }{( - 2) {}^{6} \times 1 {}^{3} } \times \frac{1}{6}$

$= \frac{3 {}^{9} }{( - 2) {}^{6} } \times \frac{1}{3} \times \frac{1}{2}$

$\frac{3 {}^{9 - 1} \times 2 {}^{6} \times 1 }{2}$

$= 3 {}^{8} \times 2 {}^{6 - 1}$

$= 3 {}^{8} \times 2 {}^{5}$