Question

[(2/3)^2]^3×(1/3)^-4×(3)^-1 ×(1/6) simplify ​

Answer 1

$[\{(\frac{2}{3})^2\}^3\times (\frac{1}{3})^{-4}\times 3^{-1}\times (\frac{1}{6})]$

$=[\{(\frac{4}{9})\}^3\times (3)^{4}\times\frac{1}{3} \times (\frac{1}{6})]$

$=[\frac{64}{729}\times 81\times\frac{1}{3} \times \frac{1}{6}]$

$=\frac{32}{81}$

Answer 2

Answer:

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