Question

[(2/3)^2]^3×(1/3)^-4×(3)^-1 ×(1/6) simplify ​

Answer 1

$[\{(\frac{2}{3})^2\}^3\times (\frac{1}{3})^{-4}\times 3^{-1}\times (\frac{1}{6})]$

$=[\{(\frac{4}{9})\}^3\times (3)^{4}\times\frac{1}{3} \times (\frac{1}{6})]$

$=[\frac{64}{729}\times 81\times\frac{1}{3} \times \frac{1}{6}]$

$=\frac{32}{81}$

Answer 2

Step-by-step explanation:

{(

3

2

)

2

}

3

×(

3

1

)

−4

×3

−1

×(

6

1

)]

=[\{(\frac{4}{9})\}^3\times (3)^{4}\times\frac{1}{3} \times (\frac{1}{6})]=[{(

9

4

)}

3

×(3)

4

×

3

1

×(

6

1

)]

=[\frac{64}{729}\times 81\times\frac{1}{3} \times \frac{1}{6}]=[

729

64

×81×

3

1

×

6

1

]

=\frac{32}{81}=

81

32