Question

2.3*2.3-2.3-0.3*0.3
Simplify-----------------------------------
2.3*2.3-2*2.3*0.3+0.3*0.3

Answer 1

(2.3-0.3)^2

(2)^2

4
therefore the answer is 4 by the second identity of algebra
(a-b)^2=a^2-2ab+b^2

Answer 2

Answer:

(2.3)^3-0.027/(2.3)^2+0.69+0.09 =2

Step-by-step explanation:

solution : numerator is (2.3)³ - (0.027)

can we write , 0.027 = 0.3 × 0.3 × 0.3 = (0.3)³

so, (2.3)³ - 0.027 = (2.3)³ - (0.3)³

from algebraic identity, a³ - b³ = (a - b)(a² + b² + ab)

so, (2.3)³ - (0.3)³ = (2.3 - 0.3){(2.3)² + (0.3)² + 2.3 × 0.3}

= 2{(2.3)² + 0.09 + 0.69}

= 2{(2.3)² + 0.69 + 0.09}

now, {(2.3)³ - (0.3)³}/{(2.3)² + 0.69 + 0.09}

= 2{(2.3)² + 0.69 + 0.09}/{(2.3)² + 0.69 + 0.09}

= 2

hence, answer is 2.