(2+√3/2-√3) - (2-√3/2+√3) = a+√3b
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5+2 root 3 / 7+ 4 root 3
on rationalising
(5+ root 3/ 7+4 root 3 ) x (7-4 root 3/ 7 - root 3)
{(5+2root 3)(7-4 root 3)}\(7sq - 4root 3 sq)
(35 - 20root 3 + 14root 3 - 8root 3)\(49-48)
==> 35- 14 root 3
on comparing
a = 35
b root 3 = -14 root 3
therefore b= -14
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