Math, asked by advaith85, 7 months ago

{2-3(2-3)^3}^3 please answer I need this question for exams tomorrow

Answers

Answered by pulakmath007
24

\huge\boxed{\underline{\underline{\green{Solution}}}} </p><p></p><p>

 \{2-3(2-3)^3 \}^3

 =  \{2-3( - 1)^3 \}^3

 =  \{2-3 \times( -  1) \}^3

 =  (2 + 3 )^3

 =  {5}^{3}

 = 125

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Answered by d687cyoyo
5

Answer:

{2−3(2−3)3}3

= \{2-3( - 1)^3 \}^3={2−3(−1)3}3

= \{2-3 \times( - 1) \}^3={2−3×(−1)}3

= (2 + 3 )^3=(2+3)3

= {5}^{3}=53

= 125=125

\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}PleaseMarkitBrainliest

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