Question

2+√3/2-√3=a+b√3, find the value of a and b. i will follow those who will give me correct answers and mark brainliest​

Answer 1

$\bold{ \huge{ Answer :- }}\\ \bold{\frac{2 + \sqrt{3} }{2 - \sqrt{3} } = a + b \sqrt{3} }\\ \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } = a + b \sqrt{3} \\ \frac{ {(2 + \sqrt{3} )}^{2} }{ {(2)}^{2} - {( \sqrt{3} )}^{2} } = a + b \sqrt{3} \\ \frac{4 + 3 + 4 \sqrt{3} }{4 - 3} = a + b \sqrt{3} \\ \frac{7 + 4 \sqrt{3} }{1} = a + b \sqrt{3} \\ 7 + 4 \sqrt{3} = a + b \sqrt{3} \\\bold{ \huge{ \boxed{ a = 7,b = 4 }}}$