Question

2+√3/2-√3 rationligetion​

Answer 1

please see the attachment .

mark me as brainliest

and follow me

Answer 2

$\frac{2 + \sqrt{3} }{2 - \sqrt{3} }$

Firstly Understand why we Rationalise.

Since ,

In Denominator 2-√3 there is Irrational Number√3 to make it Rational.We must have to Rationalise it.

So,

Rationalising Factor of 2-√3=2+√3

Multiply both Numerator and Denominator with 2+√3

$\frac{(2 + \sqrt{3})(2 + \sqrt{3} )}{(2 - \sqrt{3 )}(2 + \sqrt{3} ) }$

As we know

a²-b²=(a+b)(a-b)

$\frac{(2 + \sqrt{3} ) {}^{2} }{ {2}^{2} - \sqrt{3} {}^{2} } \\ \\ \frac{ {2}^{2} + \sqrt{3} {}^{2} + 2 \times 2 \sqrt{3} }{4 - 3} \\ \\ \frac{4 + 3 + 4 \sqrt{3} }{1}$

Answer=7+4√3