Question

(2^-3-2^-4)³


the numbers after

2 are exponents with a minus behind the exponents the three outside is also exponent​

Answer 1

$\huge\star\pink{solution}$

$= (2 {}^{ - 3} - 2 {}^{ - 4} ) {}^{3} \\ \\ = ( \frac{1}{2 {}^{3} } - \frac{1}{2 {}^{4} }) {}^{3} \\ \\ = (\frac{1}{8} - \frac{1}{16}) {}^{3} \\ \\ = ( \frac{1}{8 }) {}^{3} - ( \frac{1}{16}) {}^{3} - 3( \frac{1}{8} ) {}^{2} \frac{1}{16} + 3( \frac{1}{8} )( \frac{1}{16} ) {}^{2} \\ \\ = \frac{1}{512} - \frac{1}{4096} - \frac{3}{1024} + \frac{3}{2048} \\ \\ = \frac{8 - 1 - 3(4) + 3(2)}{4096} \\ \\ = \frac{1}{4096}$

formula uses

$= (a - b) {}^{3} = a {}^{3} - b {}^{3} - 3a {}^{2} b + 3ab {}^{2} \\ \\ = a {}^{ - m} = \frac{1}{a {}^{m} }$

====================

I hope it helps you