Math, asked by pcat85634, 2 months ago

2/3 )^−2 + (5 × 2)^2 − ( 1/2 )^2 + [ ( 1/7 )^−2 + (7^−2 )^0 ]​

Answers

Answered by VelvetRosee
0

Answer:

value of (2/3)^-2 + 5(2)^2 - (1/2)^2 + [ (1/7)^-2 + (7^-2)^0 ] is  72

Step-by-step explanation:

given that

(2/3)^-2 + 5(2)^2 - (1/2)^2 + [ (1/7)^-2 + (7^-2)^0 ]

first of all let us solve the negative powers;

(3/2)^2 + 5(2)^2 - (1/2)^2 + [ (7/1)^2 + (1/7^2)^0 ]

let's solve the complete equation by solving all powers ; square of any number is multiple of the same given number :

9/4 + 5(4) - (1/4) + [ (49) + (1/49)^0 ]

9/4 + 20 - (1/4) + [ (49) + 1 ]

any number power 0 is 1

9/4 + 20 - (1/4) + 50\\

(9-1)/4 +20 + 50

8/4 +70

⇒ 2 + 70

⇒ 72

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