Question

(2√3 - 2√5 ) (2√3 - 2√5 )

Answer 1

Step-by-step explanation:

$(2 \sqrt{3} - 2 \sqrt{5} )(2 \sqrt{3} - 2 \sqrt{5} ) = {(2 \sqrt{3} - 2 \sqrt{5}) }^{2} \\ = {(2 \sqrt{3)} }^{2} +( {2 \sqrt{5}) }^{2} - 2(2 \sqrt{3} )(2 \sqrt{5} ) = 12 + 20 - 8 \sqrt{15} = 32 - 8 \sqrt{15}$

Answer 2

QUESTION:-

$(2\sqrt{3} -2\sqrt{5} )(2\sqrt{3} -2\sqrt{5} )$

IDENTITY USED:-

$(a-b)^2=a^2-2ab+b^2$

EXPLANATION:-

$(2\sqrt{3} -2\sqrt{5} )(2\sqrt{3} -2\sqrt{5} )$ CAN BE WRITTEN  AS $(2\sqrt{3} -2\sqrt{5} )^2$

$(2 \sqrt{3}-2\sqrt{5}) ^2 =(2\sqrt{3})^2-2(2\sqrt{3})(2\sqrt{5})+(2\sqrt{5})$

$(2 \sqrt{3}-2\sqrt{5})^2 =12-4\sqrt{15} +20$

$(2 \sqrt{3}-2\sqrt{5}) ^2=32-4\sqrt{15}$