Math, asked by viratdixit, 1 year ago

((-2)^3)^2+5^-3÷5^-5-(-1/2)^0

Answers

Answered by yani1994

(-2)^3×2 + 1/5^3÷ 1/5^-5 - 1
256 + 5^5 ÷ 5^3 -1
256 + 5^5-3 - 1
256 + 5^2 -1
256 + 25 -1
256 + 24
280
if any step not clear then ask me

yani1994: how

yani1994: pls solve it

yani1994: can u send pic this question to do again

viratdixit: ((-2)^3)^2+5^-3÷5^-5-(-1÷2)^0

viratdixit: I dont know the answer . the answer given in my maths book is 2^3×11

yani1994: okk I will try again

yani1994: you can send ur question pic

yani1994: okk hi meet ur answer

yani1994: ((-2)^3)^2 + 5^-3 ÷ 5^-5 - (-1/2)^0 so (-8)^2 + 1/5^3 ÷ 1/5^5 - 1 => 64 + 5^5 ÷5^3 -1 => 64 + 5^5-3 - 1 => 64 +5^2 -1 => 64 +25 -1 => 89 -1 => 88 => 2^3 × 11

yani1994: ((-2)^3)^2 + 5^-3 ÷ 5^-5 - (-1/2)^0 so (-8)^2 + 1/5^3 ÷ 1/5^5 - 1 => 64 + 5^5 ÷5^3 -1 => 64 + 5^5-3 - 1 => 64 +5^2 -1 => 64 +25 -1 => 89 -1 => 88 => 2^3 × 11 . I hope u satisfied

Answered by harshitavermakhushi

Answer:

Step-by-step explanation:

((-2)^3)^2+5^-3÷5^-5-(-1/2)^0

=(-8)^2+5^((-3-(-5))-1

=64+5^(-3+5)-1

=64+5^2-1

=64+25-1

=88

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