Question

(2/√3) + 2
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Answer 1

Answer:

Solution:-

(√2-√3)^2

= [√2]^2 + [√3]^2 -2[√2][2√3]. ( As (a-b)^2 = a^2 +b^2 -2ab)

= 2 + 3 - 2[√6]

= 5–2[√6]

= 5-√24

Hence,

Take values of √2=1.414 and √3=1.732 and than apply the algebraic identity of

(a-b)²=a²+b²-2ab

(CAUTION:-see √a*√b is not equal to √ab mind this its real maths we are talking if you wanna know the reason mes.sage me why)

Hence proved :)