Question

(2×+3)(3×-2)+2=0 using quadratic equations​

Answer 1

Hi there !!

(2x+3)(3x-2)+2=0

→6x²-4x+9x-6+2=0

→6x²+5x-4 =0

→6x² -3x +8x-4 =0

→3x(2x-1) +4(2x-1)

→(2x-1) +(3x+4)

→x= 1/2 and -4/3

Ignoring negative value

Hence,

$x = \frac{1}{2}$

Thankyou :)