√2+√3/3√2-2√3=a-b√6
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here typing mistake , I think
question is (V2 + V3)/( 32 -2V3) = a -bv6
( v2 + v3)( 3v2 + 2v3)/{ (3v2)?
(6 + 3v6 + 2v6 + 6 )/( 18 - 12)
(12 + 5V6)/6
2 +( 5/12)v6 = a - bv6
so, a = 2 and b= 5/12
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a is root2 and b iis 3.. ...
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