(√2+√3) (3√2-2√3)=a-b√6
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(√2+√3) (3√2-2√3)
=6-2√6+3√6-6
= √6
=0-(-√6)
a=0
b=-1
=6-2√6+3√6-6
= √6
=0-(-√6)
a=0
b=-1
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Hey !!
Check the attachment.
Hope it helps :)
Check the attachment.
Hope it helps :)
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