Question

√2+√3/3√2-2√3=(a+b√6) find the value of a and b

Answer 1

Recognise that you can remove sqrt(6) common in denominator.

Then multiply both numerator and denominator by sqrt(3)+sqrt(2)

On simplification, you'll get (sqrt(2)+sqrt(3))^2/sqrt(6)*(3–2)

Now, it is simplified as {5+2*sqrt(6)}/sqrt(6)}

So, a=2 and b=5/6