Question

2√3-3√2/√3+√2=a-b√6,find the value of a and b

Answer 1

plzz mark as brainliest

Answer 2

here you go ☆☆

_______________________________________

it's the concept of rationalizing denomerator.

$\frac{2 \sqrt{3} - 3 \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$\frac{2 \sqrt{3} - 3 \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3 } - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\frac{6 - 2 \sqrt{6} - 3 \sqrt{6} + 6}{ { \sqrt{3} }^{2} - { \sqrt{2} }^{2} }$

$\frac{ 12 - 5 \sqrt{6} }{3 - 2}$

$\frac{ 12 - 5 \sqrt{6} }{1}$

so a = 12 and b = -5
________________________________

hope it helps:)