Question

(2/3)'3×(2/3)'6=(2/3)'2k-3​

find the k in this equation​

Answer 1

Answer:

k = 15/4

Step-by-step explanation:

(2/3)^(3)×(2/3)^(6) = (4/9)^(2k-3)

(2/3)^(3+6) = {(2/3)²}^(2k-3)

(2/3)^(9) = (2/3)^(4k-6)

4k-6 = 9

4k = 9+6

4k = 15

k = 15/4

Step-by-step explanation: