Question

(2/3)^3 × (2/3)^-6 = (2/3)^x-4 find the value of x in the following

Answer 1

Answer:

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Answer 2

Answer:

x=2

Step-by-step explanation:

$\bold{ { \frac{2}{3} }^{3} \times \frac{2}{3}^{ - 6} = { \frac{2}{3} }^{x - 4} } \\ \\ \bold{ \frac{2}{3} ^{3 - 6} = { \frac{2}{3} }^{x - 4} } \\ \\ equating \: powers \\ \\ \bold{x - 4 = - 2} \\ \\ \bold{x = 2} \\ \\ \color{blue} \bold{formula \: \: {x}^{a} \times {x}^{b} = {x}^{a + b} }$

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